1/x^4/x^2+4/x=0

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Solution for 1/x^4/x^2+4/x=0 equation: 


D( x )

x^4 = 0

x = 0

x^2 = 0

x^4 = 0

x^4 = 0

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+(1/(x^4))/(x^2) = 0

4*x^-1+x^-6 = 0

t_1 = x^-1

1*t_1^6+4*t_1^1 = 0

t_1^6+4*t_1 = 0

t_1*(t_1^5+4) = 0

1*t_1^5 = -4 // : 1

t_1^5 = -4

t_1^5 = -4 // ^ 1/5

t_1 = -4^(1/5)

t_1 = 0

t_1 = 0

t_1 = -4^(1/5)

x^-1+4^(1/5) = 0

1*x^-1 = -4^(1/5) // : 1

x^-1 = -4^(1/5)

-1 < 0

1/(x^1) = -4^(1/5) // * x^1

1 = -4^(1/5)*x^1 // : -4^(1/5)

1/(-4^(1/5)) = x^1

x = 1/(-4^(1/5))

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = 1/(-4^(1/5))

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